# A.B.C. ## 9 thoughts on “ A.B.C. ”

1. Shaktijin says:
Simplify (a+b-c)(a+b+c) Expand by multiplying each term in the first expression by each term in the second expression. Simplify terms. Tap for more steps Combine the opposite terms in. Tap for more steps Reorder the factors in the terms and. Subtract from. Add and. .
2. Yozshushura says:
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3. Doktilar says:
Let us first define some basic formulas of boolean algebra that we're gonna need for the solution 1. (X+X)=X 2. (X.X)=X 3. (X+1)=1 4. 1.X=X Now let us get to the problem (A+B)(B+C)(A+C) =(AB+AC+BC+BB)(A+C) {Multiplying the first two terms} =(AB+AC.
4. Tujin says:
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5. Malrajas says:
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6. Akisida says:
Feb 24,  · Let A,B and C be sets. Prove that (A-B)-C=(A-C)-(B-C). Attempted solution: Suppose x \\in (A-B)-C. Since x \\in (A-B)-C this means that x \\in A but x \\notin B and x \\notin C. I'm not sure how to show how these two statements are equal.
7. Kakazahn says:
Purplemath. Venn diagrams can be used to express the logical (in the mathematical sense) relationships between various sets. The following examples should help you understand the notation, terminology, and concepts relating Venn diagrams and set notation.. Let's say that our universe contains the numbers 1, 2, 3, and 4, so U = {1, 2, 3, 4}.Let A be the set containing the numbers 1 and 2; that.
8. Nir says:
My personal preference is a=b=c=d for the following reasons. It is concise, saves lines; It conveys the concept that (a/b/c/d) are initialized to the same thing, that they are related; However, caveat: Don't do that if a/b/c/d are not related (and just happens to be initialized to 1).
9. Mibei says:
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